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Hydraulic Oil Cooling Load

The heat the hydraulic oil has to give up, from pump power and drive type — servo drive, conventional hydraulics or all-electric. Free and no sign-up required; you can switch to the other 14 tools from the tabs above.

Machine Selection
Process
Auxiliaries & Cost
Share of heat transferred to the oil20 %
Oil cooling load6.0 kW
Required water flow17.2 L/min

On a servo drive the pump only turns while there is movement, so the heat passing into the oil is roughly a third of that on conventional hydraulics. Oil temperature above 50 °C lowers the viscosity and shortens seal life.

These calculations produce guide values; the final selection has to be based on the part geometry, the mold design and the data from the material manufacturer. For an assessment specific to your application, contact our technical support team.

How is this calculated?

In a hydraulic system the part of the energy produced by the pump that does not turn into work heats the oil. That share depends on the drive type: roughly 20% on a servo drive (the pump only turns while there is movement) and 30 – 35% on conventional hydraulics. An all-electric machine has no hydraulic circuit.

Load [kW] = Pump power [kW] x Heat share
Flow [l/min] = Load x 60 / (4.19 x deltaT)

If the oil temperature exceeds 50 °C, the viscosity drops, internal leakage rises and seal life shortens. When the cooling water is dirty or scaled, the heat exchanger quietly loses capacity — oil that runs hot in summer is often the first sign of exactly that.

The method, the formula and the limits of each tool are explained directly underneath it, and the explanation changes with the tab you select. The results are engineering guide values; for an assessment specific to your application when choosing the final machine and equipment, contact our technical team.

Prepared by:Uğur Çamlıca· Teknik Part · Sources: manufacturer documentation and field practice